Physics math problems

Formulas #2 and #3 are the deconstruction of the force vector (if you don’t know what that means, you should go over the material) – these are the formulas that link the force (which we know) to the angle (which we want to find out)

  • Solve
    Remember our “Understand the Problem” part? We said there that since the acceleration is on the horizontal, we will need to consider the horizontal force or projection of that force. And we know that F=ma, which means that the acceleration is a direct result of the force. What is the force on the box, then?
    This is the force responsible for the acceleration – and since the only force at play is that done by the pulling man, this has to be the horizontal projection of that man’s our trigonometric formula for the projection? Let’s take the horizontal component, and plug in what we have:
    1. Which is our answer.
  • Verify Your Results
    Well, let’s think about this for a moment. The man pulls the rope with an angle. But the projection (35N) is not too far off of the actual force he uses (40N) – it’s quite logical, then, that the angle will be relatively small – even smaller than 45 degrees.
  • Psst… You’ve done it!

    Unbeknownst to most students, every time the school floors are waxed, the physics teachers get together to have a barrel of phun doing friction experiments in their socks (uhm - they do have clothes on; its just that they don't have any shoes on their feet). On one occasion, Mr. London applies a horizontal force to accelerate Mr. Schneider (mass of 84 kg) rightward at a rate of m/s/s. If the coefficient of friction between Mr. Schneider 's socks and the freshly waxed floors is , then with what force (in Newtons) must Mr. London be pulling?

    Physics math problems

    physics math problems


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